B è¹`n ã@sdd„Zdd„ZdS)cCs$x|dk r||krdS|j}qWdS)a2Is ``resource1`` 'inside' ``resource2``? Return ``True`` if so, else ``False``. ``resource1`` is 'inside' ``resource2`` if ``resource2`` is a :term:`lineage` ancestor of ``resource1``. It is a lineage ancestor if its parent (or one of its parent's parents, etc.) is an ancestor. NTF)Ú __parent__)Z resource1Z resource2©rúX/home/kop/projects/devel/pgwui/test_venv/lib/python3.7/site-packages/pyramid/location.pyÚinsides  rccs<x6|dk r6|Vy |j}Wqtk r2d}YqXqWdS)am Return a generator representing the :term:`lineage` of the :term:`resource` object implied by the ``resource`` argument. The generator first returns ``resource`` unconditionally. Then, if ``resource`` supplies a ``__parent__`` attribute, return the resource represented by ``resource.__parent__``. If *that* resource has a ``__parent__`` attribute, return that resource's parent, and so on, until the resource being inspected either has no ``__parent__`` attribute or which has a ``__parent__`` attribute of ``None``. For example, if the resource tree is:: thing1 = Thing() thing2 = Thing() thing2.__parent__ = thing1 Calling ``lineage(thing2)`` will return a generator. When we turn it into a list, we will get:: list(lineage(thing2)) [ , ] N)rÚAttributeError)ÚresourcerrrÚlineage!s   rN)rrrrrrÚs